Arrange Na, Na^+, F, F^- in the decreasing or | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) The atomic radius of a neutral atom is larger than its cation because the removal of an electron decreases the electron-electron repulsion and inc

Vedclass · Accepted Answer

$Na > F^- > Na^+ > F$

Vedclass · Answer

(A) The atomic radius of a neutral atom is larger than its cation because the removal of an electron decreases the electron-electron repulsion and increases the effective nuclear charge. Thus, $Na > Na^+$.The ionic radius of an anion is larger than its neutral atom because the addition of an electron increases the electron-electron repulsion, leading to a decrease in the effective nuclear charge per electron. Thus, $F^- > F$.Comparing the sizes based on atomic/ionic radii values (in $pm$):$Na$ $(186 \ pm)$, $F^-$ $(136 \ pm)$, $Na^+$ $(86 \ pm)$, $F$ $(64 \ pm)$.Therefore, the decreasing order of size is $Na > F^- > Na^+ > F$.

Arrange $Na, Na^+, F, F^-$ in the decreasing order of their radii (size).

Similar Questions

Which of the following represents the correct order of ionic radii?

Choose the correct order of atomic radii of fluorine and neon (in $pm$) out of the options given below and justify your answer.

The increasing order of the atomic radius of $Si, S, Na, Mg, Al$ is

Which of the following anions has the smallest radius?

In which periods are $Na$ and $F$ located? What is the order of their atomic radii and why?

Vedclass Test Series

Exam Paper Generator

Online Exam Module