Identify the elements represented by the following electronic configurations:
$(a)$ $[He] \, 2s^1$
$(b)$ $[Ne] \, 3s^2 \, 3p^3$
$(c)$ $[Ar] \, 4s^2 \, 3d^1$

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(N/A) The electronic configuration is $[He] \, 2s^1$. The atomic number $Z = 2 + 1 = 3$. Thus,the element is Lithium $(Li)$.
$(b)$ The electronic configuration is $[Ne] \, 3s^2 \, 3p^3$. The atomic number $Z = 10 + 2 + 3 = 15$. Thus,the element is Phosphorus $(P)$.
$(c)$ The electronic configuration is $[Ar] \, 4s^2 \, 3d^1$. The atomic number $Z = 18 + 2 + 1 = 21$. Thus,the element is Scandium $(Sc)$.

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If $Br^{-}$ configuration is $[Ar]\, 3d^{10}\,4s^2\,4p^6$,then $Br^{+2}$ configuration will be identical to which element?

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Match the column:
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$A$. The orbital which has two angular nodes $P$. $4d_{x^2-y^2}$
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