The $F-t$ graph for an object is shown in the figure. What will be the magnitude of the change in momentum $(\Delta p)$ in the interval of $0.03\, s$ from the start?
(N/A) The change in momentum $(\Delta p)$ is equal to the impulse,which is the area under the $F-t$ graph.
Area = $\text{Force} \times \text{Time interval}$
Area = $10\, N \times 0.03\, s$
Area = $0.3\, N\cdot s$
Therefore,the change in momentum $\Delta p = 0.3\, kg\cdot m/s$.
Area = $\text{Force} \times \text{Time interval}$
Area = $10\, N \times 0.03\, s$
Area = $0.3\, N\cdot s$
Therefore,the change in momentum $\Delta p = 0.3\, kg\cdot m/s$.
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