Match the items in Column-I with their corres | vedclass

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(B) The values for the astronomical units are as follows:$(1)$ Light year is the distance light travels in one year,which is approximately $9.46 	ime

Vedclass · Accepted Answer

$1-b, 2-a, 3-c$

Vedclass · Answer

(B) The values for the astronomical units are as follows:$(1)$ Light year is the distance light travels in one year,which is approximately $9.46 	imes 10^{15} \ m$. Thus,$(1-b)$.$(2)$ Parsec is a unit of distance used in astronomy,equal to approximately $3.08 	imes 10^{16} \ m$. Thus,$(2-a)$.$(3)$ $1 \ AU$ (Astronomical Unit) is the average distance between the Earth and the Sun,which is approximately $1.496 	imes 10^{11} \ m$. Thus,$(3-c)$.Therefore,the correct matching is $(1-b, 2-a, 3-c)$.

Column-$I$	Column-$II$
$(1)$ Light year	$(a)$ $3.08 \times 10^{16} \ m$
$(2)$ Parsec	$(b)$ $9.46 \times 10^{15} \ m$
$(3)$ $1 \ AU$	$(c)$ $1.496 \times 10^{11} \ m$

Match the items in Column-$I$ with their corresponding values in Column-$II$.

Column-$I$ Column-$II$

$(1)$ Light year $(a)$ $3.08 \times 10^{16} \ m$

$(2)$ Parsec $(b)$ $9.46 \times 10^{15} \ m$

$(3)$ $1 \ AU$ $(c)$ $1.496 \times 10^{11} \ m$

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Match the items in Column-$I$ with their corresponding values in Column-$II$. Column-$I$ Column-$II$ $(1)$ Light year $(a)$ $3.08 \times 10^{16} \ m$ $(2)$ Parsec $(b)$ $9.46 \times 10^{15} \ m$ $(3)$ $1 \ AU$ $(c)$ $1.496 \times 10^{11} \ m$