$SO_2 + H_2S \to$ product. The final product is
- A$H_2O + S$
- B$H_2SO_4$
- C$H_2SO_3$
- D$H_2S_2O_3$
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Similar Questions
What is the value of $n$-factor of $[Fe(CN)_6]^{-4}$ in the given reaction?
$[Fe(CN)_6]^{-4} \xrightarrow{MnO_4^-/H^{+}} Fe^{+3} + CO_2 + NO_3^-$
$[Fe(CN)_6]^{-4} \xrightarrow{MnO_4^-/H^{+}} Fe^{+3} + CO_2 + NO_3^-$
In the titration of $KMnO_{4}$ and oxalic acid in acidic medium,the change in oxidation number of carbon at the end point is
In dilute alkaline solution,$MnO_4^-$ changes to:
Medium
View SolutionAssign $A, B, C, D$ from the given type of reaction.
$Na_2CO_3 + PbSO_4 \longrightarrow PbCO_3 \downarrow + Na_2SO_4$
$Na_2CO_3 + PbSO_4 \longrightarrow PbCO_3 \downarrow + Na_2SO_4$
Medium
View Solution$2MnO_4^{-} + 5H_2O_2 + 6H^{+} \to 2Z + 5O_2 + 8H_2O$. In this reaction $Z$ is
Medium
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