Fill in the blanks:
$1.$ The atomic radii of the elements of the third transition series are .......... to those of the corresponding elements of the second transition series.
$2.$ Samarium melts at .......... $K$.
$3.$ The color of lanthanoid ions is due to the presence of .......... electrons.
$1.$ The atomic radii of the elements of the third transition series are .......... to those of the corresponding elements of the second transition series.
$2.$ Samarium melts at .......... $K$.
$3.$ The color of lanthanoid ions is due to the presence of .......... electrons.
(N/A) $1.$ The atomic radii of the elements of the third transition series are almost identical to those of the corresponding elements of the second transition series due to lanthanoid contraction.
$2.$ Samarium melts at $1347 \ K$.
$3.$ The color of lanthanoid ions is due to the presence of $f$-electrons (specifically $f-f$ transitions).
$2.$ Samarium melts at $1347 \ K$.
$3.$ The color of lanthanoid ions is due to the presence of $f$-electrons (specifically $f-f$ transitions).
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Similar Questions
Determine the correct $(T)$ and incorrect $(F)$ statements from the following:
$(a)$ The symbol for Lanthanum is $La$.
$(b)$ The name of the element $Lu$ is Lanthanum.
$(c)$ The electronic configuration of $La^{3+}$ and $Ce^{4+}$ contains $4f^0$.
$(a)$ The symbol for Lanthanum is $La$.
$(b)$ The name of the element $Lu$ is Lanthanum.
$(c)$ The electronic configuration of $La^{3+}$ and $Ce^{4+}$ contains $4f^0$.
Difficult
View SolutionWhich elements exhibit nearly identical properties?
Easy
View SolutionThe ion with $4f^7$ configuration is
The common stable oxidation states of $Eu$ and $Gd$ are respectively
Identify the lanthanoid element from the following.
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