State the hybridization and draw the structures of $PCl_3$ and $PCl_5$.
(N/A) For $PCl_3$: The central phosphorus atom is $sp^3$ hybridized. It has $3$ bond pairs and $1$ lone pair,resulting in a trigonal pyramidal geometry.
For $PCl_5$: The central phosphorus atom is $sp^3d$ hybridized. It has $5$ bond pairs and $0$ lone pairs,resulting in a trigonal bipyramidal geometry.
For $PCl_5$: The central phosphorus atom is $sp^3d$ hybridized. It has $5$ bond pairs and $0$ lone pairs,resulting in a trigonal bipyramidal geometry.
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Similar Questions
The ion that has $sp^{3}d^{2}$ hybridization for the central atom is :
MediumAIIMS 2019
View SolutionMatch the following:
List-$I$ List-$II$ $(a)$ $SF_6$ $(i)$ $sp^3d^2$ $(b)$ $PCl_5$ (ii) $sp^3d$ $(c)$ $XeF_4$ (iii) $sp^3d^3$ $(d)$ $IF_7$ (iv) $sp^3d^2$
The correct answer is:
| List-$I$ | List-$II$ |
| $(a)$ $SF_6$ | $(i)$ $sp^3d^2$ |
| $(b)$ $PCl_5$ | (ii) $sp^3d$ |
| $(c)$ $XeF_4$ | (iii) $sp^3d^3$ |
| $(d)$ $IF_7$ | (iv) $sp^3d^2$ |
The correct answer is:
Which of the following overlapping is not present in $XeO_3$ molecule?
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Medium
View SolutionThe shape of the ethylene molecule is:
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