Explain the calculation of the number of atom | vedclass

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(B) In a body-centered cubic $(bcc)$ unit cell:$1$. There is one atom at each of the $8$ corners of the cube. Each corner atom contributes $\frac{1}{8

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$2$

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(B) In a body-centered cubic $(bcc)$ unit cell:$1$. There is one atom at each of the $8$ corners of the cube. Each corner atom contributes $\frac{1}{8}$ to the unit cell.Contribution from corners $= 8 	imes \frac{1}{8} = 1$ atom.$2$. There is one atom at the body center of the cube,which is entirely contained within the unit cell.Contribution from the body center $= 1 	imes 1 = 1$ atom.$3$. Total number of atoms per unit cell $= 1 + 1 = 2$ atoms.

Explain the calculation of the number of atoms in a body-centered cubic $(bcc)$ unit cell.

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