$(i)$ What is the energy of an electron for hydrogen in $J \ atom^{-1}$ and $J \ mol^{-1}$?
$(ii)$ Calculate the energy of this electron per mole for the first transition ($n=1$ to $n=2$).
$(iii)$ Calculate the ionization energy of hydrogen.

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(N/A) $(i)$ The energy of an electron in the ground state $(n=1)$ of hydrogen is given by $E_n = -2.18 \times 10^{-18} \ J \ atom^{-1}$.
In $J \ mol^{-1}$,$E = (-2.18 \times 10^{-18} \ J \ atom^{-1}) \times (6.022 \times 10^{23} \ atom \ mol^{-1}) = -1.312 \times 10^6 \ J \ mol^{-1} = -1312 \ kJ \ mol^{-1}$.
$(ii)$ For the first transition ($n=1$ to $n=2$),$\Delta E = E_2 - E_1 = -2.18 \times 10^{-18} \times (\frac{1}{2^2} - \frac{1}{1^2}) = 1.635 \times 10^{-18} \ J \ atom^{-1}$.
Per mole,$\Delta E = 1.635 \times 10^{-18} \times 6.022 \times 10^{23} = 9.846 \times 10^5 \ J \ mol^{-1} = 984.6 \ kJ \ mol^{-1}$.
$(iii)$ Ionization energy is the energy required to move an electron from $n=1$ to $n=\infty$. $\Delta E = E_{\infty} - E_1 = 0 - (-1312 \ kJ \ mol^{-1}) = 1312 \ kJ \ mol^{-1}$.

Explore More

Similar Questions

Which will be the first emission line in the infrared region of the hydrogen atomic spectrum?

If the shortest wavelength of the hydrogen atom in the Lyman series is $x$,then the longest wavelength in the Balmer series of $He^+$ is:

Which of the following is the radius of the first orbit of $He^{+}$ (in $pm$)?

The value of the work function of a metal $X$ is $3.1 \ eV$. What is its threshold frequency (in $Hz$)? (Given: $h = 6.62 \times 10^{-34} \ J \cdot s$)

In the hydrogen atomic spectrum,a series limit is found at $12186.3 \ cm^{-1}$. To which series does it belong?

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo