At which location on Earth is the effective a | vedclass

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(B) The effective acceleration due to gravity $g'$ at a latitude $\phi$ is given by $g' = g - \omega^2 R \cos^2 \phi$,where $g$ is the acceleration du

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At the poles

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(B) The effective acceleration due to gravity $g'$ at a latitude $\phi$ is given by $g' = g - \omega^2 R \cos^2 \phi$,where $g$ is the acceleration due to gravity at the poles,$\omega$ is the angular velocity of the Earth,and $R$ is the radius of the Earth.At the poles,$\phi = 90^\circ$,so $\cos 90^\circ = 0$. Thus,$g' = g$,which is the maximum value.At the equator,$\phi = 0^\circ$,so $\cos 0^\circ = 1$. Thus,$g' = g - \omega^2 R$,which is the minimum value.

At which location on Earth is the effective acceleration due to gravity maximum?

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