Find the angle between the velocity vector an | vedclass

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(C) In uniform circular motion,the speed of the particle remains constant,but the direction of velocity changes continuously.The acceleration in unifo

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$90$

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(C) In uniform circular motion,the speed of the particle remains constant,but the direction of velocity changes continuously.The acceleration in uniform circular motion is centripetal acceleration,which is directed towards the center of the circular path.The velocity vector is always tangent to the circular path at any given point.Since the radius (position vector) is perpendicular to the tangent at any point on the circle,the centripetal acceleration (directed along the radius) is always perpendicular to the velocity vector.Therefore,the angle between the velocity vector $\vec{v}$ and the acceleration vector $\vec{a}$ is $90^{\circ}$.

Find the angle between the velocity vector and the acceleration vector for a particle in uniform circular motion. (in $^{\circ}$)

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