(C) Both balls will reach the ground at the same time. Since both balls are released from the same height $h$ and their initial vertical velocity comp

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Both balls will reach the ground at the same time.

(C) Both balls will reach the ground at the same time. Since both balls are released from the same height $h$ and their initial vertical velocity components are zero $(u_y = 0)$,the time taken to reach the ground is determined by the vertical motion equation: $h = \frac{1}{2}gt^2$. Solving for $t$,we get $t = \sqrt{\frac{2h}{g}}$. Since $h$ and $g$ are the same for both,the time $t$ is identical for both balls.

Class 11 Physics 3-2.Motion in Plane Horizontal Projectile Motion

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$A$ ball is dropped from a high tower,and another ball is thrown horizontally from the same position. Which ball will reach the ground first?

A
The ball dropped vertically.
B
The ball thrown horizontally.
C
Both balls will reach the ground at the same time.
D
It depends on the mass of the balls.

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3-2.Motion in Plane

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Horizontal Projectile Motion

$A$ particle is projected at an angle of $45^{\circ}$ with the horizontal with an initial kinetic energy $K$. What will be its kinetic energy at the highest point?

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$A$ particle aimed at a target,projected with an angle $15^{\circ}$ with the horizontal,is short of the target by $10 \ m$. If projected with an angle of $45^{\circ}$,it is away from the target by $15 \ m$. Then the angle of projection to hit the target is:

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$A$ cricketer can throw a ball to a maximum horizontal distance of $100 \; m$. How much high above (in $m$) the ground can the cricketer throw the same ball?

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$A$ particle is projected with kinetic energy $K$ at an angle of $60^o$ with the horizontal. The kinetic energy of the particle at the maximum height is . . . . . . .

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$A$ particle of mass $m$ is projected with velocity $v$ making an angle of $45^{\circ}$ with the horizontal. When the particle lands on the level ground,the magnitude of the change in its momentum will be

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$A$ ball is dropped from a high tower,and another ball is thrown horizontally from the same position. Which ball will reach the ground first?

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$A$ particle is projected at an angle of $45^{\circ}$ with the horizontal with an initial kinetic energy $K$. What will be its kinetic energy at the highest point?

$A$ particle aimed at a target,projected with an angle $15^{\circ}$ with the horizontal,is short of the target by $10 \ m$. If projected with an angle of $45^{\circ}$,it is away from the target by $15 \ m$. Then the angle of projection to hit the target is:

$A$ cricketer can throw a ball to a maximum horizontal distance of $100 \; m$. How much high above (in $m$) the ground can the cricketer throw the same ball?

$A$ particle is projected with kinetic energy $K$ at an angle of $60^o$ with the horizontal. The kinetic energy of the particle at the maximum height is . . . . . . .

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