Write the formula for centripetal acceleratio | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(A) In uniform circular motion,the centripetal acceleration is given by $a_c = \omega^2 r$,where $\omega$ is the angular velocity and $r$ is the radiu

Vedclass · Accepted Answer

$a_c = 4\pi^2 f^2 r$

Vedclass · Answer

(A) In uniform circular motion,the centripetal acceleration is given by $a_c = \omega^2 r$,where $\omega$ is the angular velocity and $r$ is the radius of the circular path.We know that the relationship between angular velocity $\omega$ and frequency $f$ is $\omega = 2\pi f$.Substituting this value into the centripetal acceleration formula:$a_c = (2\pi f)^2 r$$a_c = 4\pi^2 f^2 r$Thus,the formula for centripetal acceleration in terms of frequency is $a_c = 4\pi^2 f^2 r$.

Write the formula for centripetal acceleration in terms of frequency in uniform circular motion.

Similar Questions

What is the angular velocity of the second hand of a clock?

$A$ particle is performing $U.C.M.$ along the circumference of a circle of diameter $50 \ cm$ with a frequency of $2 \ Hz$. The acceleration of the particle in $m/s^2$ is:

$A$ particle is moving in $U.C.M.$ with speed $V$ and radius $R$. The angular acceleration of the particle is

$A$ motorcyclist going round in a circular track at a constant speed has:

Two bodies of equal masses revolve in circular orbits of radii $R_1$ and $R_2$ with the same period. Their centripetal forces are in the ratio:

Vedclass Test Series

Exam Paper Generator

Online Exam Module