$C$, $Si$ and $Ge$ have the same lattice structure. Why is $C$ an insulator while $Si$ and $Ge$ are intrinsic semiconductors?

Vedclass pdf generator app on play store
Vedclass iOS app on app store
(A) The $4$ bonding electrons of $C$, $Si$, and $Ge$ reside in the second, third, and fourth orbits, respectively.
As the principal quantum number increases, the valence electrons are further from the nucleus and less tightly bound.
Consequently, the energy gap $(E_g)$ required to excite an electron from the valence band to the conduction band is highest for $C$ $(\,5.4 \ eV)$, intermediate for $Si$ $(\,1.1 \ eV)$, and lowest for $Ge$ $(\,0.7 \ eV)$.
For $C$, the energy gap is so large that thermal energy at room temperature is insufficient to excite electrons, making it an insulator.
In $Si$ and $Ge$, the energy gap is small enough that a significant number of electrons can be thermally excited to the conduction band at room temperature, allowing them to act as intrinsic semiconductors.

Explore More

Similar Questions

The Fermi energy level of an intrinsic semiconductor lies:

In a good conductor,the energy gap between the conduction band and the valence band is:

State the value of the energy band gap difference between the valence band $(E_V)$ and the conduction band $(E_C)$ for $C$ (Diamond), $Si$, and $Ge$.

How does an intrinsic semiconductor behave at $0 \ K$?

Give a brief explanation of solid state semiconductor electronics.

Vedclass Products

For Students

Vedclass Test Series

Mock tests in real JEE/NEET style with performance analysis. 5-day free trial.

Start Free Trial
For Teachers

Exam Paper Generator

Generate Set A/B/C/D exam papers from 7.5L+ questions in 2 minutes. 3 chapters free.

Try Free
For Institutes

Online Exam Module

Live online exams with unlimited students, 360° analytics & white-label branding.

See Demo