XeO_4 molecule is tetrahedral having | vedclass

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Question

(C) In $XeO_4$,the central atom $Xe$ is in its $8^{th}$ oxidation state.It undergoes $sp^{3}$ hybridization involving one $5s$ and three $5p$ orbitals

Vedclass · Accepted Answer

Four $p\pi-d\pi$ bonds

Vedclass · Answer

(C) In $XeO_4$,the central atom $Xe$ is in its $8^{th}$ oxidation state.It undergoes $sp^{3}$ hybridization involving one $5s$ and three $5p$ orbitals.These four $sp^{3}$ hybrid orbitals form four $\sigma$ bonds with four oxygen atoms.Additionally,the four unpaired electrons in the $5d$ orbitals of $Xe$ form four $p\pi-d\pi$ bonds with the $2p$ orbitals of the oxygen atoms.Therefore,the molecule contains four $p\pi-d\pi$ bonds.

$XeO_4$ molecule is tetrahedral having

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