1, m^3 of water is brought inside a lake up t | vedclass

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(C) The formula for bulk modulus $K$ is given by $K = \frac{P}{\Delta V/V}$, where $P$ is the change in pressure, $V$ is the initial volume, and $\Del

Vedclass · Accepted Answer

$9.1	imes10^{-4}\, m^3$

Vedclass · Answer

(C) The formula for bulk modulus $K$ is given by $K = \frac{P}{\Delta V/V}$, where $P$ is the change in pressure, $V$ is the initial volume, and $\Delta V$ is the change in volume.Rearranging for $\Delta V$, we get $\Delta V = \frac{PV}{K}$.The pressure at depth $h$ is $P = hho g = 200 	imes 10^3 	imes 10 = 2 	imes 10^6\, N/m^2$.The bulk modulus is $K = 22000\, 	ext{atm} = 22000 	imes 10^5 = 2.2 	imes 10^9\, N/m^2$.Given $V = 1\, m^3$, substituting the values:$\Delta V = \frac{2 	imes 10^6 	imes 1}{2.2 	imes 10^9} = \frac{2}{2200} = \frac{1}{1100} \approx 9.09 	imes 10^{-4}\, m^3$.Rounding to the nearest option, $\Delta V \approx 9.1 	imes 10^{-4}\, m^3$.

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