Polyethylene is prepared from calcium carbide as follows:
$CaC_2 + 2H_2O \to Ca(OH)_2 + C_2H_2$
$C_2H_2 + H_2 \to C_2H_4$
$nC_2H_4 \to (-CH_2-CH_2-)_n$
Calculate the amount of polyethylene produced from $64 \ kg$ of $CaC_2$. (in $kg$)

Match the polymers given in Column-$I$ with their commercial names given in Column-$II$.

Column-$I$	Column-$II$
$A$. Polyester of glycol and phthalic acid	$i$. Novolac
$B$. Copolymer of $1,3$-butadiene and styrene	$ii$. Glyptal
$C$. Phenol and formaldehyde resin	$iii$. Buna-$S$
$D$. Polyester of glycol and terephthalic acid	$iv$. Buna-$N$
$E$. Copolymer of $1,3$-butadiene and acrylonitrile	$v$. Dacron

Match the following:

Polymer	Type
$A$. Bakelite	$P$. Homo polymer
$B$. Nylon-$6$	$Q$. Condensation polymer
$C$. Terylene	$R$. Polyester
$D$. $PHBV$	$S$. Copolymer

Match materials given in Column-$I$ with the polymers given in Column-$II$.

Column-$I$	Column-$II$
$A$. Natural rubber latex	$i$. Nylon
$B$. Wood laminates	$ii$. Neoprene
$C$. Ropes and fibres	$iii$. Dacron
$D$. Polyester fabric	$iv$. Melamine formaldehyde resins
$E$. Synthetic rubber	$v$. Urea-formaldehyde resins
$F$. Unbreakable crockery	$vi$. cis-polyisoprene

Match the following:

$A$. Teflon	$I$. $SnCl_2$
$B$. Anionic polymerisation	$II$. $C_2F_4$
$C$. Cationic polymerisation	$III$. Bakelite
$D$. Thermosetting polymer	$IV$. Polystyrene
	$V$. $RLi$

The correct answer is:

An organic compound $P$ with molecular formula $C_{9}H_{18}O_{2}$ decolorizes bromine water and also shows a positive iodoform test. $P$ on ozonolysis followed by treatment with $H_{2}O_{2}$ gives $Q$ and $R$. While compound $Q$ shows a positive iodoform test,compound $R$ does not. $Q$ and $R$ on oxidation with pyridinium chlorochromate $(PCC)$ followed by heating give $S$ and $T$,respectively. Both $S$ and $T$ show a positive iodoform test.
Complete copolymerization of $500$ moles of $Q$ and $500$ moles of $R$ gives one mole of a single acyclic copolymer $U$.
[Given,atomic mass: $H=1, C=12, O=16$ ]
$(1)$ Sum of the number of oxygen atoms in $S$ and $T$ is. . . . . .
$(2)$ The molecular weight of $U$ is
Give the answer for questions $(1)$ and $(2)$.