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(A) The $pH$ of an aqueous solution of a salt depends on the strength of the parent acid. The salt $NaClO$ is derived from the weak acid $HClO$. The s

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$NaClO$

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(A) The $pH$ of an aqueous solution of a salt depends on the strength of the parent acid. The salt $NaClO$ is derived from the weak acid $HClO$. The salts $NaClO_2$,$NaClO_3$,and $NaClO_4$ are derived from $HClO_2$,$HClO_3$,and $HClO_4$ respectively. As the oxidation state of chlorine increases,the acidic strength of the corresponding oxoacid increases $(HClO Since $HClO$ is the weakest acid among these,its conjugate base $ClO^-$ is the strongest base. $A$ stronger conjugate base undergoes greater hydrolysis to produce more $OH^-$ ions,resulting in a higher $pH$. Therefore,$NaClO$ will have the highest $pH$.

Column $I$	Column $II$
$A$. $CH_3COONa$	$i$. Almost neutral,$pH > 7$ or $< 7$
$B$. $NH_4Cl$	$ii$. Acidic,$pH < 7$
$C$. $NaNO_3$	$iii$. Alkaline,$pH > 7$
$D$. $CH_3COONH_4$	$iv$. Neutral,$pH = 7$

Which of the following aqueous solutions will have the highest $pH$?

Similar Questions

An aqueous solution of $CH_3COONa$ will be

Which of the following will not undergo hydrolysis in water?

Match the column $I$ with column $II$ and mark the appropriate choice.

Column $I$ Column $II$

$A$. $CH_3COONa$ $i$. Almost neutral,$pH > 7$ or $< 7$

$B$. $NH_4Cl$ $ii$. Acidic,$pH < 7$

$C$. $NaNO_3$ $iii$. Alkaline,$pH > 7$

$D$. $CH_3COONH_4$ $iv$. Neutral,$pH = 7$

Calculate the percentage of hydrolysis in $0.01 \ M$ aqueous solution of $NaOCN$ ($K_b$ for $OCN^{-} = 10^{-10}$)

Predict if the solutions of the following salts are neutral,acidic,or basic: $NaCl, KBr, NaCN, NH_4NO_3, NaNO_2$ and $KF$.

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