When ammonia is heated with cupric oxide,each | vedclass

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(B) The reaction between ammonia $(NH_3)$ and cupric oxide $(CuO)$ is given by: $2NH_3 + 3CuO \rightarrow N_2 + 3Cu + 3H_2O$. In this reaction,the oxi

Vedclass · Accepted Answer

$3$

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(B) The reaction between ammonia $(NH_3)$ and cupric oxide $(CuO)$ is given by: $2NH_3 + 3CuO \rightarrow N_2 + 3Cu + 3H_2O$. In this reaction,the oxidation state of nitrogen changes from $-3$ in $NH_3$ to $0$ in $N_2$. For one molecule of $NH_3$,the nitrogen atom loses $3$ electrons to go from an oxidation state of $-3$ to $0$. Thus,each molecule of ammonia loses $3$ electrons.

When ammonia is heated with cupric oxide,each molecule of ammonia loses how many electrons?

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