In the reaction P_4 + 3KOH + 3H_2O to PH_3 + | vedclass

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(C) In the reaction $P_4 + 3KOH + 3H_2O 	o PH_3 + 3KH_2PO_2$,the oxidation state of phosphorus changes as follows:$1$. In $P_4$,the oxidation state o

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both oxidized and reduced

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(C) In the reaction $P_4 + 3KOH + 3H_2O 	o PH_3 + 3KH_2PO_2$,the oxidation state of phosphorus changes as follows:$1$. In $P_4$,the oxidation state of $P$ is $0$.$2$. In $PH_3$,the oxidation state of $P$ is $-3$ (reduction).$3$. In $KH_2PO_2$,the oxidation state of $P$ is $+1$ (oxidation).Since phosphorus is simultaneously oxidized and reduced,this is a disproportionation reaction.

In the reaction $P_4 + 3KOH + 3H_2O \to PH_3 + 3KH_2PO_2$,phosphorus is .........

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