Which of the following gases present in the a | vedclass

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(D) White lead is chemically $2PbCO_3 \cdot Pb(OH)_2$. When exposed to air containing hydrogen sulfide $(H_2S)$,it reacts to form lead sulfide $(PbS)$

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$H_2S$

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(D) White lead is chemically $2PbCO_3 \cdot Pb(OH)_2$. When exposed to air containing hydrogen sulfide $(H_2S)$,it reacts to form lead sulfide $(PbS)$,which is black in color. The chemical reaction is: $Pb(OH)_2 \cdot 2PbCO_3 + 3H_2S \rightarrow 3PbS + 2CO_2 + 4H_2O$. Thus,$H_2S$ is the gas responsible for blackening the surface.

Which of the following gases present in the air blackens the surface painted with white lead?

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