Which of the following is the correct order o | vedclass

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(D) The reducing power of an element is related to its ability to lose electrons,which is determined by its standard oxidation potential. For Group $1

Vedclass · Accepted Answer

$Al > Ga > In > Tl$

Vedclass · Answer

(D) The reducing power of an element is related to its ability to lose electrons,which is determined by its standard oxidation potential. For Group $13$ elements,the standard electrode potential $(E^\circ)$ values for the reaction $M^{3+} + 3e^- \rightarrow M$ are: $Al^{3+}/Al = -1.66 \ V$ $Ga^{3+}/Ga = -0.56 \ V$ $In^{3+}/In = -0.34 \ V$ $Tl^{3+}/Tl = +1.26 \ V$ Since $Al$ has the most negative reduction potential,it is the strongest reducing agent. As we move down the group,the tendency to form $M^{3+}$ ions decreases due to the inert pair effect,and the stability of the $+1$ oxidation state increases. Therefore,the reducing power decreases in the order: $Al > Ga > In > Tl$.

Which of the following is the correct order of the reducing power of $Al, Ga, In,$ and $Tl$?

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