The heat released when 0.8 , g of carbon is c | vedclass

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(A) $i) \, C + O_2 \longrightarrow CO_2$ Heat for $12 \, g$ ($1$ mole) of $C = \frac{x}{0.8} 	imes 12 = 15x \, cal$. $ii) \, C + \frac{1}{2} O_2 \lon

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$x - y$

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(A) $i) \, C + O_2 \longrightarrow CO_2$ Heat for $12 \, g$ ($1$ mole) of $C = \frac{x}{0.8} 	imes 12 = 15x \, cal$. $ii) \, C + \frac{1}{2} O_2 \longrightarrow CO$ Heat for $12 \, g$ ($1$ mole) of $C = \frac{y}{0.8} 	imes 12 = 15y \, cal$. Subtracting $(ii)$ from $(i)$: $CO + \frac{1}{2} O_2 \longrightarrow CO_2$ Heat of reaction for $1 \, mole$ $(28 \, g)$ of $CO = (15x - 15y) \, cal$. Heat released for $1.86 \, g$ of $CO = \frac{15(x - y)}{28} 	imes 1.86 \approx 0.996(x - y) \approx (x - y) \, cal$.

The heat released when $0.8 \, g$ of carbon is converted to carbon dioxide is $x \, cal$. The heat released when $0.8 \, g$ of carbon is converted to carbon monoxide is $y \, cal$. If $x > y$,then the heat released when $1.86 \, g$ of carbon monoxide is converted to carbon dioxide will be:

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