Which of the following solutions will have th | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) To determine the maximum $pH$,we need to find the solution with the highest concentration of hydroxide ions $[OH^-]$.$A$. $10^{-3} \ M \ NH_4OH$:

Vedclass · Accepted Answer

$10^{-3} \ M \ Ba(OH)_2$

Vedclass · Answer

(D) To determine the maximum $pH$,we need to find the solution with the highest concentration of hydroxide ions $[OH^-]$.$A$. $10^{-3} \ M \ NH_4OH$: This is a weak base. $[OH^-] = \sqrt{K_b 	imes C} $B$. $10^{-1} \ M \ NH_4OH$: This is a weak base. $[OH^-] = \sqrt{K_b 	imes 10^{-1}} \approx 10^{-3} \ M$ (assuming $K_b \approx 10^{-5}$).$C$. $10^{-3} \ M \ NaOH$: This is a strong base. $[OH^-] = 10^{-3} \ M$.$D$. $10^{-3} \ M \ Ba(OH)_2$: This is a strong base. $[OH^-] = 2 	imes 10^{-3} \ M$.Comparing the $[OH^-]$ concentrations: $2 	imes 10^{-3} \ M > 10^{-3} \ M > 	ext{weak base concentrations}$.Since $Ba(OH)_2$ provides the highest $[OH^-]$ concentration,it will have the highest $pOH$ and consequently the highest $pH$.

Which of the following solutions will have the maximum $pH$?

Similar Questions

$0.001 \ mol$ of a strong electrolyte $M(OH)_2$ is dissolved to make $20 \ mL$ of a saturated solution. Calculate its $pH$ $(K_w = 1 \times 10^{-14})$.

$x \ mg$ of $Mg(OH)_2$ (molar mass $= 58 \ g/mol$) is required to be dissolved in $1.0 \ L$ of water to produce a $pH$ of $10.0$ at $298 \ K$. The value of $x$ is $........... mg$ ($Nearest$ $integer$). ($Given$: $Mg(OH)_2$ is assumed to dissociate completely in $H_2O$)

How many moles of $HCl$ must be removed from $1 \ L$ of an aqueous $HCl$ solution to change its $pH$ from $2$ to $3$?

Which would decrease the $pH$ of $25 \ cm^3$ of a $0.01 \ M$ solution of hydrochloric acid?

If the $pH$ of a solution of an alkali metal hydroxide is $13.6$,the concentration of hydroxide is

Vedclass Test Series

Exam Paper Generator

Online Exam Module