For the reaction PCl_{3(g)} + Cl_{2(g)} right | vedclass

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Question

(A) The given reaction is $PCl_{3(g)} + Cl_{2(g)} \rightleftharpoons PCl_{5(g)}$.Here,the change in the number of moles of gaseous species is $\Delta

Vedclass · Accepted Answer

$0.61$

Vedclass · Answer

(A) The given reaction is $PCl_{3(g)} + Cl_{2(g)} ightleftharpoons PCl_{5(g)}$.Here,the change in the number of moles of gaseous species is $\Delta n_g = 1 - (1 + 1) = -1$.The temperature $T = 250 + 273 = 523 \ K$.The relationship between $K_p$ and $K_c$ is given by $K_p = K_c(RT)^{\Delta n_g}$.Substituting the values: $K_p = 26 	imes (0.0821 	imes 523)^{-1}$.$K_p = \frac{26}{0.0821 	imes 523} \approx \frac{26}{42.94} \approx 0.605 \approx 0.61$.

For the reaction $PCl_{3(g)} + Cl_{2(g)} \rightleftharpoons PCl_{5(g)}$,the value of $K_c$ is $26$ at $250 \ ^oC$. The value of $K_p$ at this temperature will be ...........

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