For an AB type ionic substance,which ratio of | vedclass

Name: Exam Paper Generator | JEE NEET Paper Generator | Vedclass
Brand: Vedclass
Rating: 5 (35 reviews)

Question

(D) For an $AB$ type ionic substance,the van't Hoff factor $i$ is given by $i = 1 + \alpha$,where $\alpha$ is the degree of dissociation. Since $0 \le

Vedclass · Accepted Answer

$5 : 2$

Vedclass · Answer

(D) For an $AB$ type ionic substance,the van't Hoff factor $i$ is given by $i = 1 + \alpha$,where $\alpha$ is the degree of dissociation. Since $0 \leq \alpha \leq 1$,the value of $i$ ranges from $1$ to $2$. The ratio of theoretical molecular mass $(M_{th})$ to experimental molecular mass $(M_{exp})$ is equal to the van't Hoff factor $i$ $(i = M_{th} / M_{exp})$. Therefore,the ratio $M_{th} / M_{exp}$ must be in the range $[1, 2]$. Among the given options,$5/2 = 2.5$,which is greater than $2$. Thus,$5 : 2$ is not a consistent ratio.

For an $AB$ type ionic substance,which ratio of theoretical to experimental molecular mass is not consistent?

Similar Questions

If a $0.01 \ m$ aqueous solution of an electrolyte freezes at $-0.056 \ ^{\circ}C$,calculate the van't Hoff factor $(i)$ for the electrolyte. (Cryoscopic constant of water $K_{f} = 1.86 \ K \ kg \ mol^{-1}$)

$A$ solute undergoes association in a solution to form a dimer. Which of the following values of the van't Hoff factor $i$ is possible?

When acetic acid is dissolved in benzene,its molecular mass:

The molecular weight of benzoic acid dissolved in benzene is found to be ............ $g/mol$.

The observed molar mass determined for $Na_2SO_4$ by the freezing point depression method is $50.0 \ g/mol$. The theoretical molar mass of $Na_2SO_4$ is $142 \ g/mol$. What will be the degree of dissociation $\alpha$ for $Na_2SO_4$ in water?

Vedclass Test Series

Exam Paper Generator

Online Exam Module