The osmotic pressure of blood at 300 K is 8. | vedclass

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(B) For isotonic solutions,the osmotic pressure $(\pi)$ is the same. Given: $\pi = 8.21 \ atm$,$T = 300 \ K$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}

Vedclass · Accepted Answer

$60$

Vedclass · Answer

(B) For isotonic solutions,the osmotic pressure $(\pi)$ is the same. Given: $\pi = 8.21 \ atm$,$T = 300 \ K$,$R = 0.0821 \ L \ atm \ K^{-1} \ mol^{-1}$. Using the formula $\pi = CRT$,where $C$ is the molar concentration in $mol \ L^{-1}$: $8.21 = C 	imes 0.0821 	imes 300$ $C = \frac{8.21}{0.0821 	imes 300} = \frac{8.21}{24.63} = \frac{1}{3} \ mol \ L^{-1}$. Glucose $(C_6H_{12}O_6)$ has a molar mass of $180 \ g \ mol^{-1}$. Concentration in $g \ L^{-1} = C 	imes 	ext{Molar Mass} = \frac{1}{3} 	imes 180 = 60 \ g \ L^{-1}$.

The osmotic pressure of blood at $300 \ K$ is $8.21 \ atm$. What is the concentration of an aqueous glucose solution that is isotonic with this blood in $g \ L^{-1}$?

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