If the mole fraction of the solute in benzene | vedclass

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Question

(A) Given: Mole fraction of solute $(x_2)$ = $0.2$. Since the sum of mole fractions is $1$,the mole fraction of solvent (benzene,$C_6H_6$) is $x_1 = 1

Vedclass · Accepted Answer

$3.2$

Vedclass · Answer

(A) Given: Mole fraction of solute $(x_2)$ = $0.2$. Since the sum of mole fractions is $1$,the mole fraction of solvent (benzene,$C_6H_6$) is $x_1 = 1 - 0.2 = 0.8$. The molar mass of benzene $(C_6H_6)$ is $M_1 = (6 	imes 12) + (6 	imes 1) = 78 \ g/mol$. Molality $(m)$ is given by the formula: $m = \frac{x_2 	imes 1000}{x_1 	imes M_1}$. Substituting the values: $m = \frac{0.2 	imes 1000}{0.8 	imes 78} = \frac{200}{62.4} \approx 3.205 \ m$. Rounding to the nearest given option,the answer is $3.2$.

If the mole fraction of the solute in benzene is $0.2$,then the molality of the solution is .........

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