If the cation is present in the tetrahedral v | vedclass

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Question

(B) The radius ratio rule for ionic crystals determines the coordination number and the geometry of the void occupied by the cation.For a tetrahedral

Vedclass · Accepted Answer

$0.225 - 0.414$

Vedclass · Answer

(B) The radius ratio rule for ionic crystals determines the coordination number and the geometry of the void occupied by the cation.For a tetrahedral void,the coordination number of the cation is $4$.The limiting radius ratio for a tetrahedral void is calculated as $0.225$.The range of the radius ratio for tetrahedral coordination is $0.225 - 0.414$.Therefore,the correct option is $B$.

If the cation is present in the tetrahedral void,what is the radius ratio ${r_ + }/{r_ - }$?

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