Calculate the number of unit cells in 1 , g o | vedclass

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Question

(A) For a $bcc$ unit cell,the number of atoms per unit cell $(Z)$ is $2$. The number of unit cells is given by the formula: $	ext{Number of unit cell

Vedclass · Accepted Answer

$1.3 	imes 10^{22}$

Vedclass · Answer

(A) For a $bcc$ unit cell,the number of atoms per unit cell $(Z)$ is $2$. The number of unit cells is given by the formula: $	ext{Number of unit cells} = \frac{	ext{Total number of atoms}}{Z} = \frac{W 	imes N_A}{M 	imes Z}$. Given: $W = 1 \, g$,$M = 23 \, g/mol$,$N_A = 6.022 	imes 10^{23} \, mol^{-1}$,$Z = 2$. $	ext{Number of unit cells} = \frac{1 	imes 6.022 	imes 10^{23}}{23 	imes 2} = \frac{6.022 	imes 10^{23}}{46} \approx 1.309 	imes 10^{22}$. Thus,the number of unit cells is $1.3 	imes 10^{22}$.

Calculate the number of unit cells in $1 \, g$ of sodium metal that crystallizes in a $bcc$ structure. $(Na = 23 \, amu)$

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