In a compound XY,the atoms of element Y form | vedclass

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(C) In an $fcc$ structure,the number of atoms of element $Y$ per unit cell is $4$. The number of tetrahedral voids $(T.V.)$ is equal to $2 	imes (	e

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$XY_2$

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(C) In an $fcc$ structure,the number of atoms of element $Y$ per unit cell is $4$. The number of tetrahedral voids $(T.V.)$ is equal to $2 	imes (	ext{number of atoms}) = 2 	imes 4 = 8$. Element $X$ occupies $25\%$ of the tetrahedral voids,so the number of $X$ atoms $= 8 	imes \frac{25}{100} = 8 	imes \frac{1}{4} = 2$. The ratio of $X:Y$ is $2:4$,which simplifies to $1:2$. Therefore,the molecular formula of the compound is $XY_2$.

In a compound $XY$,the atoms of element $Y$ form an $fcc$ structure,while the atoms of element $X$ occupy $25\%$ of the tetrahedral voids. The molecular formula of the compound will be .......

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