For which of the following substances will a | vedclass

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(D) The condition $a 
e b 
e c$ and $\alpha = \beta = \gamma = 90^o$ represents the orthorhombic crystal system.$BaSO_4$ (barium sulfate) and $KNO_3

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$NaCl$

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(D) The condition $a 
e b 
e c$ and $\alpha = \beta = \gamma = 90^o$ represents the orthorhombic crystal system.$BaSO_4$ (barium sulfate) and $KNO_3$ (potassium nitrate) crystallize in the orthorhombic system.$TiO_2$ (titanium dioxide) exists in different forms,but the rutile form is tetragonal $(a = b 
e c, \alpha = \beta = \gamma = 90^o)$.$NaCl$ (sodium chloride) crystallizes in the cubic system $(a = b = c, \alpha = \beta = \gamma = 90^o)$.Since the question asks for which substance the orthorhombic condition does $NOT$ hold,both $TiO_2$ and $NaCl$ do not fit the criteria. However,in standard textbook contexts for this specific question,$NaCl$ is the classic example of a cubic system,making it the most distinct answer.

For which of the following substances will $a \ne b \ne c$ and $\alpha = \beta = \gamma = 90^o$ $NOT$ hold true?

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