The reduction of chloroform with Zn and HCl ( | vedclass

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(D) The reduction of chloroform $(CHCl_3)$ with zinc $(Zn)$ and alcoholic hydrochloric acid $(HCl)$ is a partial reduction process.The reaction is as

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Methylene chloride

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(D) The reduction of chloroform $(CHCl_3)$ with zinc $(Zn)$ and alcoholic hydrochloric acid $(HCl)$ is a partial reduction process.The reaction is as follows:$CHCl_3 + 2[H] \xrightarrow{Zn/HCl(alc.)} CH_2Cl_2 + HCl$In this reaction,one chlorine atom is replaced by a hydrogen atom,resulting in the formation of methylene chloride $(CH_2Cl_2)$.

The reduction of chloroform with $Zn$ and $HCl$ (alc.) gives ..........

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