What will be the product $A$ in the following reaction?
$C_6H_5CCl_3 \xrightarrow{1 \text{ eq. of } Br_2/Fe} A$

Given below are two statements:
Statement $I$: Benzene is nitrated to give nitrobenzene,which on further treatment with $CH_{3}COCl / AlCl_{3}$ will give the product shown in the image.
Statement $II$: $NO_{2}$ group is a $m$-directing and deactivating group.
In the light of the above statements,choose the most appropriate answer:

Which of the following groups deactivates the benzene ring towards electrophilic substitution reaction?

Rank the following compounds in order of decreasing rate of reaction with alkoxide ion $(CH_3CH_2O^{-})$ in a nucleophilic aromatic substitution reaction:
$1$. $1$-bromo-$2$-nitrobenzene
$2$. $1$-bromo-$3$-nitrobenzene
$3$. $1$-bromo-$2,4$-dinitrobenzene
$4$. $1$-bromo-$3,4$-dinitrobenzene

Which reaction shows the correct major product?

Assertion : $p-$nitroacetophenone $(p-O_2N-C_6H_4-COCH_3)$ is prepared by Friedel-Crafts acylation of nitrobenzene.
Reason : Nitrobenzene easily undergoes electrophilic substitution reaction.