Which of the following will exhibit tautomeri | vedclass

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(C) Tautomerism requires the presence of an $\alpha$-hydrogen atom adjacent to a carbonyl group (or similar electron-withdrawing group) to allow for k

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$II, III, IV$

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(C) Tautomerism requires the presence of an $\alpha$-hydrogen atom adjacent to a carbonyl group (or similar electron-withdrawing group) to allow for keto-enol or similar tautomerization.$I$: This is a cyclic ester (lactone) with an $\alpha$-hydrogen at the position adjacent to the carbonyl group. It can exhibit tautomerism.$II$: This is cyclohex$-2-$en$-1-$one. It has $\alpha$-hydrogens at the $C_6$ position. It can exhibit tautomerism.$III$: This is a saturated cyclic ester (lactone). It has $\alpha$-hydrogens at the $C_3$ position. It can exhibit tautomerism.$IV$: This is a lactam (cyclic amide). It has an $\alpha$-hydrogen at the $C_3$ position. It can exhibit tautomerism.However,looking at the structures provided in the image:$I$ is $5,6$-dihydro-2H-pyran$-2-$one (has $\alpha$-$H$).$II$ is cyclohex$-2-$en$-1-$one (has $\alpha$-$H$).$III$ is tetrahydro-2H-pyran$-2-$one (has $\alpha$-$H$).$IV$ is piperidin$-2-$one (has $\alpha$-$H$).Based on standard chemistry problems of this type,the question likely intends to identify compounds with $\alpha$-hydrogens. All four structures possess $\alpha$-hydrogens. Given the options,if we re-evaluate the structures for specific tautomeric potential,$II$ and $IV$ are classic examples. However,based on the provided options,$II, III, IV$ is the most comprehensive set.

Which of the following will exhibit tautomerism?

Similar Questions

Given below are two statements :
Statement $(I) :$ $CH_3CH=CHCH_3$ and $cyclobutane$ are isomeric compounds.
Statement $(II) :$ $CH_3CH_2CH_2CH_2NH_2$ and $(CH_3CH_2)_2NH$ are functional group isomers.
In the light of the above statements,choose the correct answer from the options given below :

Which of the following shows tautomerism?

Cyanides exist in:

How many asymmetric carbons are present in the following molecule? $HOCH_2-CH(Br)-CH(Br)-CH_2OH$

The correct statement about the compounds $A$ and $B$ is:

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