The number of stereoisomers for 2-chloro-4-me | vedclass

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(B) The structure of $2-$chloro$-4-$methylhex$-2-$ene is $CH_3-C(Cl)=CH-CH(CH_3)-CH_2-CH_3$.There is one double bond at $C-2$ which can show geometric

Vedclass · Accepted Answer

$4$

Vedclass · Answer

(B) The structure of $2-$chloro$-4-$methylhex$-2-$ene is $CH_3-C(Cl)=CH-CH(CH_3)-CH_2-CH_3$.There is one double bond at $C-2$ which can show geometrical isomerism ($cis$ and $trans$ forms).There is one chiral center at $C-4$ (the carbon attached to $-CH_3$,$-H$,$-CH_2CH_3$,and $-CH=C(Cl)CH_3$ groups).Since there is one double bond capable of geometrical isomerism $(n=1)$ and one chiral center $(m=1)$,the total number of stereoisomers is given by $2^n 	imes 2^m = 2^1 	imes 2^1 = 4$.

The number of stereoisomers for $2-$chloro$-4-$methylhex$-2-$ene is .............

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