According to the E and Z nomenclature,which i | vedclass

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(A) In the $E-Z$ system,the priority of groups attached to each carbon of the double bond is determined by the Cahn-Ingold-Prelog $(CIP)$ rules based

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$1-$chloro$-1-$propen$-1-$ol

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(A) In the $E-Z$ system,the priority of groups attached to each carbon of the double bond is determined by the Cahn-Ingold-Prelog $(CIP)$ rules based on atomic number.If the groups of higher priority are on opposite sides of the double bond,the isomer is designated as $E$ (from the German word 'entgegen',meaning opposite).If the groups of higher priority are on the same side,the isomer is designated as $Z$ (from the German word 'zusammen',meaning together).In option $A$,the structure is $1$-chloro-$1$-propen-$1$-ol. On the left carbon,$Cl$ (atomic number $17$) has higher priority than $H$ (atomic number $1$). On the right carbon,$OH$ (oxygen,atomic number $8$) has higher priority than $CH_3$ (carbon,atomic number $6$). Since the higher priority groups ($Cl$ and $OH$) are on opposite sides,this is the $E$ isomer.

According to the $E$ and $Z$ nomenclature,which isomer is $E$?

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