Chlorination of toluene in the presence of li | vedclass

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(D) $1$. Chlorination of toluene in the presence of light and heat (free radical substitution) yields benzal chloride $(C_6H_5CHCl_2)$ or benzyl chlor

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Benzyl alcohol

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(D) $1$. Chlorination of toluene in the presence of light and heat (free radical substitution) yields benzal chloride $(C_6H_5CHCl_2)$ or benzyl chloride $(C_6H_5CH_2Cl)$ depending on the extent of chlorination. Assuming side-chain chlorination to benzyl chloride: $C_6H_5CH_3 + Cl_2 \xrightarrow{h
u} C_6H_5CH_2Cl + HCl$. $2$. Subsequent reaction with aqueous $NaOH$ (nucleophilic substitution) replaces the chlorine atom with a hydroxyl group: $C_6H_5CH_2Cl + NaOH(aq) ightarrow C_6H_5CH_2OH + NaCl$. $3$. The product formed is benzyl alcohol. Since benzyl alcohol is not explicitly listed in the options provided,and assuming the question implies hydrolysis of benzyl chloride,the correct product is benzyl alcohol.

Chlorination of toluene in the presence of light and heat followed by reaction with aqueous $NaOH$ gives ...................

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