What will be $C$ in the following reaction?
$C_6H_5CH_3$ $\xrightarrow{\text{Oxidation}} A$ $\xrightarrow{NaOH} B$ $\xrightarrow[\Delta]{\text{sodalime}} C$
$C_6H_5CH_3$ $\xrightarrow{\text{Oxidation}} A$ $\xrightarrow{NaOH} B$ $\xrightarrow[\Delta]{\text{sodalime}} C$
- A$C_6H_5OH$
- B$C_6H_6$
- C$C_6H_5COONa$
- D$C_6H_5ONa$
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