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(B) The chemical formula for potassium hexachloroplatinate $(IV)$ is $K_2[PtCl_6]$.In this complex,the central metal ion is $Pt^{4+}$.The atomic numbe

Vedclass · Accepted Answer

$86$

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(B) The chemical formula for potassium hexachloroplatinate $(IV)$ is $K_2[PtCl_6]$.In this complex,the central metal ion is $Pt^{4+}$.The atomic number of $Pt$ is $78$.The number of electrons in $Pt^{4+}$ is $78 - 4 = 74$.The ligand $Cl^-$ is a monodentate ligand,and there are $6$ such ligands.Each $Cl^-$ ligand donates $2$ electrons to the central metal ion.Total electrons donated by $6$ $Cl^-$ ligands = $6 	imes 2 = 12$.$EAN = (	ext{Number of electrons in metal ion}) + (	ext{Number of electrons donated by ligands})$.$EAN = 74 + 12 = 86$.

Calculate the $EAN$ (Effective Atomic Number) of platinum in potassium hexachloroplatinate $(IV)$.

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