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(D) For a complex to exhibit both geometrical and optical isomerism,it must have geometrical isomers where at least one isomer is chiral (optically ac

Vedclass · Accepted Answer

$[Pt(en)_2Cl_2]$

Vedclass · Answer

(D) For a complex to exhibit both geometrical and optical isomerism,it must have geometrical isomers where at least one isomer is chiral (optically active).$1$. $[Pt(NH_3)_2Cl_2]$ is a square planar complex,which shows geometrical isomerism but not optical isomerism.$2$. $[Pt(NH_3)_2Cl_4]$ is an octahedral complex,which shows geometrical isomerism but not optical isomerism.$3$. $[Pt(en)_3]^{4+}$ is an octahedral complex,which shows optical isomerism but not geometrical isomerism.$4$. $[Pt(en)_2Cl_2]$ is an octahedral complex. It exists as $cis$ and $trans$ isomers. The $cis$-isomer is optically active because it lacks a plane of symmetry,while the $trans$-isomer is optically inactive. Thus,it exhibits both geometrical and optical isomerism.

Which of the following complexes exhibits both geometrical and optical isomerism? $(en = \text{ethylenediamine})$

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