The number of possible geometric isomers for | vedclass

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(C) For a square planar complex of the type $[Mabcd]$,where all four ligands are different,the number of geometric isomers is $3$.These isomers are fo

Vedclass · Accepted Answer

$3$

Vedclass · Answer

(C) For a square planar complex of the type $[Mabcd]$,where all four ligands are different,the number of geometric isomers is $3$.These isomers are formed by fixing one ligand (e.g.,$a$) and arranging the other three ligands $(b, c, d)$ in different positions relative to it.The three possible arrangements are:$1$. $a$ trans to $b$ (with $c$ trans to $d$)$2$. $a$ trans to $c$ (with $b$ trans to $d$)$3$. $a$ trans to $d$ (with $b$ trans to $c$)Thus,the total number of geometric isomers is $3$.

The number of possible geometric isomers for a square planar complex $[Mabcd]$ is ............. ($M =$ central metal,$a, b, c, d =$ monodentate ligands).

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