(C) Let the oxidation state of $Fe$ be $x$. The oxidation state of $Na$ is $+1$,$NH_3$ is $0$,$CN^-$ is $-1$,and $H_2O$ is $0$. The sum of oxidation s

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(C) Let the oxidation state of $Fe$ be $x$. The oxidation state of $Na$ is $+1$,$NH_3$ is $0$,$CN^-$ is $-1$,and $H_2O$ is $0$. The sum of oxidation states in a neutral complex is zero: $3(+1) + x + 1(0) + 5(-1) + 2(0) = 0$ $3 + x - 5 = 0$ $x - 2 = 0$ $x = +2$ Therefore,the oxidation state of $Fe$ is $+2$.