Identify the product formed when cis-but-2-en | vedclass

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(A) The reaction of $cis-but-2-ene$ with $Baeyer's$ reagent (cold,dilute alkaline $KMnO_4$) is a $syn-hydroxylation$ reaction. This reaction adds two

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(A) The reaction of $cis-but-2-ene$ with $Baeyer's$ reagent (cold,dilute alkaline $KMnO_4$) is a $syn-hydroxylation$ reaction. This reaction adds two hydroxyl $(-OH)$ groups to the same side of the double bond. For $cis-but-2-ene$,the $syn-addition$ of two $-OH$ groups results in the formation of $meso-butane-2,3-diol$ because the molecule has a plane of symmetry. Therefore,the correct product is $meso-butane-2,3-diol$.

Identify the product formed when $cis-but-2-ene$ reacts with $Baeyer's$ reagent (cold,dilute alkaline $KMnO_4$ solution).

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