(A) The decomposition reaction is: $PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$According to the stoichiometry of the reaction,$1 \ volum

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(A) The decomposition reaction is: $PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$According to the stoichiometry of the reaction,$1 \ volume$ of $PH_3$ produces $\frac{3}{2} \ volumes$ of $H_2$ gas.At $t=0$: Initial volume of $PH_3 = 100 \ mL$.At $t=\text{final}$: Volume of $H_2$ produced = $\frac{3}{2} \times 100 \ mL = 150 \ mL$.Change in volume of gas = $V_{\text{final}} - V_{\text{initial}} = 150 \ mL - 100 \ mL = 50 \ mL$ increase.

Class 11 Chemistry Some Basic Concepts of Chemistry Chemical stoichiometry

Medium

$100 \ mL$ of $PH_3$ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is
$PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$

A
$50 \ mL$ increase
B
$500 \ mL$ decrease
C
$900 \ mL$ decrease
D
nil

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$100 \ mL$ of $PH_3$ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is$PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$

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$100 \ mL$ of $PH_3$ when completely decomposed produces phosphorus and hydrogen. The change in volume of the gas is
$PH_{3(g)} \longrightarrow P_{(s)} + \frac{3}{2} H_{2(g)}$