CH_3-CHCl-CHCl-CH_3 xrightarrow[dry ether]{N | vedclass

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Question

(A) $1$. The reaction of $2,3-dichlorobutane$ with $Na$ in dry ether is a dehalogenation reaction (Wurtz-like elimination),which yields $X = CH_3-CH=C

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$CH_3-CH_2-CH(OH)-CH_3$

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(A) $1$. The reaction of $2,3-dichlorobutane$ with $Na$ in dry ether is a dehalogenation reaction (Wurtz-like elimination),which yields $X = CH_3-CH=CH-CH_3$ $(But-2-ene)$.$2$. The subsequent hydroboration-oxidation of $But-2-ene$ follows anti-Markovnikov addition of water across the double bond.$3$. Since $But-2-ene$ is a symmetric alkene,the addition of $OH$ group to either carbon $2$ or $3$ results in the same product,$Y = CH_3-CH_2-CH(OH)-CH_3$ $(Butan-2-ol)$.

$CH_3-CHCl-CHCl-CH_3$ $\xrightarrow[dry \ ether]{Na} X$ $\xrightarrow[(1) \ BH_3, THF; (2) \ H_2O_2, OH^-_{(aq)}] Y$; $Y$ is:

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