KBr has NaCl structure. Its density is 2.75 | vedclass

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(B) For $NaCl$ structure,the number of formula units per unit cell $(Z)$ is $4$.Density formula: $ho = \frac{Z 	imes M}{N_{A} 	imes a^3}$Rearrangi

Vedclass · Accepted Answer

$6.6 	imes 10^{-8} \ cm$

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(B) For $NaCl$ structure,the number of formula units per unit cell $(Z)$ is $4$.Density formula: $ho = \frac{Z 	imes M}{N_{A} 	imes a^3}$Rearranging for edge length $(a)$: $a = \left[ \frac{Z 	imes M}{ho 	imes N_{A}} ight]^{1/3}$Given: $Z = 4$,$M = 119 \ g \ mol^{-1}$,$ho = 2.75 \ g \ cm^{-3}$,$N_{A} = 6.023 	imes 10^{23} \ mol^{-1}$$a = \left[ \frac{4 	imes 119}{2.75 	imes 6.023 	imes 10^{23}} ight]^{1/3}$$a = \left[ \frac{476}{16.563 	imes 10^{23}} ight]^{1/3} \approx (28.74 	imes 10^{-23})^{1/3} \approx (287.4 	imes 10^{-24})^{1/3}$$a \approx 6.6 	imes 10^{-8} \ cm$

$KBr$ has $NaCl$ structure. Its density is $2.75 \ g \ cm^{-3}$. The edge length of the unit cell will be (molar mass of $KBr$ is $119 \ g \ mol^{-1}$):

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