The IUPAC name of the given compound is: | vedclass

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(A) $1$. Identify the longest carbon chain containing the double bond. The chain has $6$ carbon atoms,so the parent alkane is hexane,and with the doub

Vedclass · Accepted Answer

$5-$Bromo$-3-$chlorohex$-1-$ene

Vedclass · Answer

(A) $1$. Identify the longest carbon chain containing the double bond. The chain has $6$ carbon atoms,so the parent alkane is hexane,and with the double bond at position $1$,it is hex$-1-$ene.$2$. Number the chain starting from the end that gives the double bond the lowest possible locant. Thus,the double bond starts at $C-1$.$3$. Identify the substituents: a bromo group $(-Br)$ is at $C-5$ and a chloro group $(-Cl)$ is at $C-3$.$4$. Arrange the substituents in alphabetical order: Bromo comes before Chloro.$5$. Combining these,the name is $5-$Bromo$-3-$chlorohex$-1-$ene.

The $IUPAC$ name of the given compound is:

Similar Questions

What is the correct structure of $4-$bromo$-3-$methylbut$-1-$ene?

The $IUPAC$ name of $H_3C-CH(C_2H_5)-CH_2-CH(OH)-CH_2Cl$ is

Rank the following groups in order of $R, S$ priority (Cahn-Ingold-Prelog priority rules,where $1$ is highest priority):
$A) -CH(CH_3)_2$
$B) -CH_2CH_2Br$
$C) -CH_2Br$
$D) -C(CH_3)_3$

The $IUPAC$ name of the compound $CH_3-CO-CH(CH_3)-CH(CHO)-CH(CH_3)_2$ is:

The $IUPAC$ name of the given structure is:

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