Identify the product C in the following react | vedclass

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(B) $1$. The reaction of $1$-bromo-$4$-chlorobenzene with $1 	ext{ mole}$ of $Mg$ in $THF$ selectively forms the Grignard reagent at the $Br$ positio

Vedclass · Accepted Answer

$4$-chlorobenzoic acid

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(B) $1$. The reaction of $1$-bromo-$4$-chlorobenzene with $1 	ext{ mole}$ of $Mg$ in $THF$ selectively forms the Grignard reagent at the $Br$ position because $C-Br$ bond is weaker than $C-Cl$ bond. Thus,$A$ is $4$-chlorophenylmagnesium bromide.$2$. The Grignard reagent $(A)$ reacts with $CO_2$ to form a magnesium carboxylate intermediate $(B)$,which is $4$-chlorophenylmagnesium carboxylate.$3$. Acidic hydrolysis $(H^+)$ of the intermediate $B$ yields $4$-chlorobenzoic acid as the final product $C$.

Identify the product $C$ in the following reaction sequence:
$1$-bromo-$4$-chlorobenzene $+ Mg (1 \text{ mole})$ $\xrightarrow{THF} A$ $\xrightarrow{CO_2} B$ $\xrightarrow{H^+} C$

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Identify the product $C$ in the following reaction sequence:$1$-bromo-$4$-chlorobenzene $+ Mg (1 \text{ mole})$ $\xrightarrow{THF} A$ $\xrightarrow{CO_2} B$ $\xrightarrow{H^+} C$