C_2H_2 xrightarrow[1% HgSO_4]{dil. H_2SO_4} A | vedclass

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Question

(A) $1.$ Hydration of ethyne: $HC \equiv CH + H_2O \xrightarrow{dil. H_2SO_4, HgSO_4} CH_3CHO$ (Ethanal,$A$)$2.$ Oxidation: $CH_3CHO \xrightarrow{[O]}

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$CH_4$

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(A) $1.$ Hydration of ethyne: $HC \equiv CH + H_2O \xrightarrow{dil. H_2SO_4, HgSO_4} CH_3CHO$ (Ethanal,$A$)$2.$ Oxidation: $CH_3CHO \xrightarrow{[O]} CH_3COOH$ (Ethanoic acid,$B$)$3.$ Neutralization: $CH_3COOH + NaOH \rightarrow CH_3COONa$ (Sodium ethanoate,$C$)$4.$ Decarboxylation: $CH_3COONa + NaOH \xrightarrow{CaO, \Delta} CH_4$ (Methane,$D$) + $Na_2CO_3$.Therefore,$[D]$ is $CH_4$.

$C_2H_2$ $\xrightarrow[1\% HgSO_4]{dil. H_2SO_4} A$ $\xrightarrow{[O]} B$ $\xrightarrow{NaOH} C$ $\xrightarrow{NaOH/CaO} D$,$[D]$ is:

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